Answer
$F_0=23.16$ with a P-value $\ltα$. Reject the null hypothesis.
There is enough evidence to conclude that at least one population mean is different from the others.
Work Step by Step
$H_0:µ_{TAC}=µ_{U-S}=µ_{Cluster}=µ_{TwC}$ versus
$H_1:$ at least one population mean is different from the others
In MINITAB, enter the Tablet-Arm Chairs values in C1, the U-Shaped values in C2, the Clusters values in C3 and in C4 enter the Tables with Chairs values.
Select Stat -> ANOVA -> One-Way
Select Response data are in a separate column for each factor level.
In Responses enter C1 C2 C3 C4
Click Ok.
$F_0=23.16$ with a P-value $\lt0.001\ltα=0.05$
