Answer
Interaction P-value $=0.167$. Do not reject the null hypothesis.
There is not enough evidence to conclude that there is an interaction between Gender and Classroom Layout.
Gender: P-value $=0.206$
There is not enough evidence to conclude that $µ_{Female}\neµ_{Male}$.
Classroom Layout: P-value $\lt0.001$
There is enough evidence to conclude that at least one of the means differs.
Work Step by Step
$H_0:$ there is no interaction between Gender and Classroom Layout.
versus
$H_1:$ there is an interaction between Gender and Classroom Layout.
In MINITAB 18, enter the data according to the table below.
Select Stat -> ANOVA -> General Linear Model -> Fit General Linear Model
In Responses enter Score (C3). In Factors enter Gender 'Classroom Layout' (C1 C2).
Click Model. In Factors and covariates highlight both Gender and Classroom Layout. Click Add (to the right of Interactions through order). Gender*'Classroom Layout' will appear in 'Terms in the model'. Click OK.
Click Ok.
The interaction P-value $=0.167$
Gender:
$H_0:µ_{Female}=µ_{Male}$ versus $H_1:µ_{Female}\neµ_{Male}$
Classroom Layout:
$H_0:µ_{TAC}=µ_{U−S}=µ_{Cluster}=µ_{TwC}$ versus $H_1:$ at least one of the means differs
Gender: P-value $=0.206$
Classroom Layout: P-value $\lt0.001$
