Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 14 - Section 14.1 - Assess Your Understanding - Applying the Concepts - Page 690: 17c

Answer

Confidence interval: $0.9191\lt β_1\lt1.2803$ We are 90% confident that as the rate of return of S&P 500 increases by 1 percent, the rate of return in United Technologies increases between 0.9191 and 1.2803 percent.

Work Step by Step

$n=11$, so: $d.f.=n-2=9$ $level~of~confidence=(1-α).100$% $90$% $=(1-α).100$% $0.9=1-α$ $α=0.1$ $t_{\frac{α}{2}}=t_{0.05}=1.833$ (According to Table VI, for d.f. = 9 and area in right tail = 0.05) $Lower~bound=b_1-t_{\frac{α}{2}}\frac{s_e}{\sqrt {Σ(x_i-x ̅)^2}}$ $Upper~bound=b_1+t_{\frac{α}{2}}\frac{s_e}{\sqrt {Σ(x_i-x ̅)^2}}$ Now, see the results obtained in the MINITAB in item (a). We can find the lower and upper bounds using the results from MINITAB. Use $\frac{s_e}{\sqrt {Σ(x_i-x ̅)^2}}=SE~Coef$ $Lower~bound=b_1-t_{\frac{α}{2}}(SE~Coef)=1.0997-1.833\times0.0985=0.9191$ $Upper~bound=b_1+t_{\frac{α}{2}}(SE~Coef)=1.0997+1.833\times0.0985=1.2803$
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