Answer
$X_{0.99}^2=5.229$
$X_{0.01}^2=30.578$
Work Step by Step
$n=16$. So:
$d.f.=n-1=15$
$level~of~confidence=(1-α).100$%
$98$% $=(1-α).100$%
$0.98=1-α$
$α=0.02$
$X_{1-\frac{α}{2}}^2=X_{0.99}^2=5.229$
(According to Table VII, for d.f. = 15 and area to the right of the critical value = 0.99)
$X_{\frac{α}{2}}^2=X_{0.01}^2=30.578$
(According to Table VII, for d.f. = 15 and area to the right of the critical value = 0.01)
