Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 9 - Review - Test - Page 472: 3b

Answer

$X_{0.95}^2=17.708$ $X_{0.05}^2=42.557$

Work Step by Step

$n=30$. So: $d.f.=n-1=29$ $level~of~confidence=(1-α).100$% $90$% $=(1-α).100$% $0.9=1-α$ $α=0.1$ $X_{1-\frac{α}{2}}^2=X_{0.95}^2=17.708$ (According to Table VII, for d.f. = 29 and area to the right of the critical value = 0.95) $X_{\frac{α}{2}}^2=X_{0.05}^2=42.557$ (According to Table VII, for d.f. = 29 and area to the right of the critical value = 0.05)
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