Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Appendix B - Graphs of Equations - Exercises - Page 424: 9

Answer

(a) $\sqrt (34)$ (b) $(\frac{11}{2}+\frac{7}{2})$

Work Step by Step

Part (a): Finding the distance between P and Q, $d(P,Q)=\sqrt ((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2})$ $d(P,Q)=\sqrt ((8-3)^{2}+(2-5)^{2})$ $d(P,Q)=\sqrt ((5)^{2}+(-3)^{2})$ $d(P,Q)=\sqrt (25+9)$ $d(P,Q)=\sqrt (34)$ Part (b): The midpoint formula is $(\frac{x_{1}+x_{2}}{2}+\frac{y_{1}+y_{2}}{2})$ Substituting the values, the formula becomes: $(\frac{8+3}{2}+\frac{2+5}{2})=(\frac{11}{2}+\frac{7}{2})$ Therefore, the coordinates of the midpoint are: $(\frac{11}{2}+\frac{7}{2})$
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