Answer
180$^{\circ}$ between 2nd and 3rd quadrant.
Work Step by Step
1. It is the same case as in 115 exercise. 180$^{\circ}$ cannot be in either quadrant.
180$^{\circ}$+360$^{\circ}$= 540$^{\circ}$
180$^{\circ}$-360$^{\circ}$=-180$^{\circ}$
Co-terminal angles always in the same quadrant as original angle.