Answer
$2$.
Work Step by Step
Using the Pythagorean theorem: $r=\sqrt{ a^{2}+b^{2}}$, here: $r=\sqrt{ {(\sqrt{3}})^{2}+{1}^{2}}=\sqrt{3+1}=\sqrt{4}=2$.
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 1 - Trigonometric Functions - Section 1.1 Angles - 1.1 Exercises - Page 9: 126
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