Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 27: 88

Answer

5

Work Step by Step

1.First lets find the values of the trig functions of the given angles. $\sin90^{\circ}=1$ $\cos270^{\circ}=0$ $\tan360^{\circ}=-0$ 2. Then just plug those values into expression: $5(1)^{2} +2(0)^{2}-(0) =5$
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