Answer
1
Work Step by Step
1. Lets find the values of given trig functions
$\sin (-90)^{\circ}=-1$
$\cos(-90)^{\circ}=0$
2.Substitute the values in the original expression:
$(-1)^{2}+(0)^{2}=1$
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 27: 91
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