Answer
sinB = $\sqrt 91$/10
cosB = 3/10
tanB = $\sqrt 91$/3
cscB = 10$\sqrt 91$/91
secB = 10/3
cotB = 3$\sqrt 91$/91
Work Step by Step
Pythagorean Theorem to determine unknown leg of triangle:
$a^{2} + b^{2} = c^{2}$
$3^{2} + b^{2} = 10^{2}$
$b^{2} = 100 - 9 = 91$
b = $\sqrt 91$
Evaluate each trignometric function:
sinB = o/h = $\sqrt 91$/10
cosB = a/h = 3/10
tanB = o/a = $\sqrt 91$/3
cscB = 10$\sqrt 91$/91
secB = h/a = 10/3
cotB = a/o = 3$\sqrt 91$/91
