Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 399: 42a

$x = 118.95~t$ $y = 65.93~t-16~t^2+2.5$

$v = 136~ft/s$ $\theta = 29^{\circ}$ $h = 2.5$ We can find an expression for $x$ in terms of $t$: $x = (v~cos~\theta)(t)$ $x = (136~cos~29^{\circ})(t)$ $x = 118.95~t$ We can find an expression for $y$ in terms of $t$: $y = (v~sin~\theta)(t)-16~t^2+h$ $y = (136~sin~29^{\circ})(t)-16~t^2+2.5$ $y = 65.93~t-16~t^2+2.5$