Answer
$x = 105.14~t$
$y = 53.57~t-16~t^2+3.2$
Work Step by Step
$v = 118~ft/s$
$\theta = 27^{\circ}$
$h = 3.2$
We can find an expression for $x$ in terms of $t$:
$x = (v~cos~\theta)(t)$
$x = (118~cos~27^{\circ})(t)$
$x = 105.14~t$
We can find an expression for $y$ in terms of $t$:
$y = (v~sin~\theta)(t)-16~t^2+h$
$y = (118~sin~27^{\circ})(t)-16~t^2+3.2$
$y = 53.57~t-16~t^2+3.2$
