Answer
$y = 0.51~x-0.00145~x^2+3.2$
Work Step by Step
From Part (a):
$x = 105.14~t$
$y = 53.57~t-16~t^2+3.2$
We can find an expression for $t$ in terms of $x$:
$x = 105.14~t$
$t = \frac{x}{105.14}$
We can substitute this value in the equation for $y$:
$y = 53.57~t-16~t^2+3.2$
$y = 53.57~(\frac{x}{105.14})-16~(\frac{x}{105.14})^2+3.2$
$y = 0.51~x-0.00145~x^2+3.2$
