Answer
Given rate constant = 3.6 x 10-3 M-1 S-1
The units are M-1 S-1
These are the units for a second order equation,.
SO the given equation is of second order. Given initial conc of X is 6 uM 2X ---> Y the rate equation is - dx/dt = k [X]^2 Half life is the time at which the conc of X is half of the initial conc we know that for a second order equation T1/2 = 1/k [A]o [A]0= 6 uM = 6 x 10-6 M k = 3.6 x 10-3 T1/2 = 1/6 x 10-6 x 3.6 x 10-3 T1/2 = 46.2963 x 106 Sec 1 year = 365 days = 365 x 24 hours = 365 x 24 x 60 x 60 s = 31536 x 103 s So T1/2 = 46.2963 x 10 6/31536 x 103 T1/2 = 1.468 years Half life is 1.468 years
Work Step by Step
Given rate constant = 3.6 x 10-3 M-1 S-1
The units are M-1 S-1
These are the units for a second order equation,.
SO the given equation is of second order. Given initial conc of X is 6 uM 2X ---> Y the rate equation is - dx/dt = k [X]^2 Half life is the time at which the conc of X is half of the initial conc we know that for a second order equation T1/2 = 1/k [A]o [A]0= 6 uM = 6 x 10-6 M k = 3.6 x 10-3 T1/2 = 1/6 x 10-6 x 3.6 x 10-3 T1/2 = 46.2963 x 106 Sec 1 year = 365 days = 365 x 24 hours = 365 x 24 x 60 x 60 s = 31536 x 103 s So T1/2 = 46.2963 x 10 6/31536 x 103 T1/2 = 1.468 years Half life is 1.468 years
