Fundamentals of Biochemistry: Life at the Molecular Level 5th Edition

Published by Wiley
ISBN 10: 1118918401
ISBN 13: 978-1-11891-840-1

Chapter 12 - Enzyme Kinetics, Inhibition, and Control - Exercises - Page 398: 1

Answer

The rate of reaction = - d[A] /dt = d[B]/dt = 5 micro B per minute = 5 x 10^-6 / min {A} = 20mM = 20x10^-3 M = 0.02 M Rate = k [A] is teh formula where Rate = 5 x10^-6 (M/min) now 5x10^-6 = 0.02 x k k = rate constant = 2.5 x 10^-4 min^-1 (see unit is min^-1)

Work Step by Step

The rate of reaction = - d[A] /dt = d[B]/dt = 5 micro B per minute = 5 x 10^-6 / min {A} = 20mM = 20x10^-3 M = 0.02 M Rate = k [A] is teh formula where Rate = 5 x10^-6 (M/min) now 5x10^-6 = 0.02 x k k = rate constant = 2.5 x 10^-4 min^-1 (see unit is min^-1)
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