Answer
8.91 x 10^4
Work Step by Step
The C.elegans genome contains 97,000 kb
f=5/97,000 = 5.2 x 10^-5
N = log(1-P)/log(1-f)
N = log (1-0.99)/log(1 - 5.2 x 10^5)
N = -2/(-2.24 x 10^5) = 8.91 x 10^4
Fundamentals of Biochemistry: Life at the Molecular Level 5th Edition
by Voet, Donald; Voet, Judith G.; Pratt, Charlotte W.
Published by
Wiley
ISBN 10:
1118918401
ISBN 13:
978-1-11891-840-1
Chapter 3 - Nucleotides, Nucleic Acids, and Genetic Information - Exercises - Page 78: 33
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