Answer
a) 5.06
b) 4.28
c) 5.46
d) 4.76
e) 3.76
Work Step by Step
Henderson-Hasselbalch equation: pH = $pK_{a}$ + log([Acetate]/[Acetic acid])
$pK_{a}$ = 4.76
pH = 4.76 + log([Acetate]/[Acetic acid])
a) pH = 4.76 + log(2/1) = 4.76 +0.3 = 5.06
b) pH = 4.76 + log(1/3) = 4.76 -0.48 = 4.28
c) pH = 4.76 + log(5/1) = 4.76 +0.7 = 5.46
d) pH = 4.76 + log(1/1) = 4.76 +0 = 4.76
e) pH = 4.76 + log(1/10) = 4.76 -1 = 3.76
