Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems - Page 72: 13

Answer

a) More soluble in 0.1 M HCl b) More soluble in 0.1 M NaOH c) More soluble in 0.1 M NaOH

Work Step by Step

A more soluble substance is one that dissociates more in the given solvent. a) Pyridine has a $pK_{a}$ of 5 and so will be more soluble in an acidic pH thus in 0.1 M HCl. b) Beta-Naphthol has a $pK_{a}$ of 10 and so will be more soluble in an alkaline pH thus in 0.1 M NaOH. c) N-Acetyltyrosine methyl ester has a $pK_{a}$ of 10 and so will be more soluble in an alkaline pH thus in 0.1 M NaOH.
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