Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Conceptual Exercises - Page 41: 83

Answer

a.) $-40°C = -40°F$ b.) $160°C$ and $320°F$ c.) $-11.4°C$ and $+11.4°F$

Work Step by Step

a.) When the Fahrenheit thermometer gives the same reading as the Celsius thermometer; Let x = the reading on the Celsius thermometer = the reading on the Fahrenheit thermometer $x °F = 1.8 * (x °C) + 32$ Note that you can write this equation with or without units. $x = 1.8x + 32$ $1.8x - x = -32$ $\frac{0.8x}{2.8} = \frac{-32}{2.8}$ $x = -40$ Therefore, x = -40 °C = -40 °F b.) When a Fahrenheit thermometer give a reading that is twice that on the Celsius thermometer; $2x °F = 1.8 * (x °C) + 32$ $2x = 1.8x + 32$ $1.8x - 2x = -32$ $\frac{-0.2x}{0.2} = \frac{-32}{0.2}$ $x = 160 °C$ Therefore, $x °C = 160 °C$ $2x °F = 320 °F$ c.) When the Fahrenheit thermometer gives a reading that is numerically the same but opposite in sign from that on the Celsius thermometer; $-x °F = 1.8 * (x °C) + 32$ $-x = 1.8x + 32$ $1.8x + x = -32$ $\frac{2.8x}{0.2} = \frac{-32}{2.8}$ $x = -11.4 °C$ Therefore, $x °C = -11.4 °C$ $-x °F = -(-11.4) °F = 11.4 °F$
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