Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Conceptual Exercises - Page 41: 84

Answer

$ N = 4.79 \times 10^{7}$ atoms

Work Step by Step

The diameter of each cesium atom is twice the size of its radius. $d = 2r$ $d = 2 \times 2.65 $ Å $d = 5.30$ Å If you place spheres next to each other, the number you can fit on a 1-inch long string is determined by their diameters. $ l = 1 $ inch $ = 0.0254$ m $ 1 $ Å $= 10^{-10}$ m $ N = \frac{l}{d} = \frac{0.0254}{5.30 \times 10^{-10} } = 4.79 \times 10^{7} $ atoms
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