Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 38: 40

Answer

a) 21.2 L b) 2.11 pt c) 0.4252 km/L

Work Step by Step

a) $$1 \space ft^3 = 28.32 \space L$$ $$ 0.750 \space ft^3 \times \frac{28.32 \space L}{1 \space ft^3} = 21.2 \space L$$ b) $$8 \space pt = 4 \space qt$$ $$1.057 \space qt = 1 \space L$$ $$ 1.00 \space L \times \frac{1.057 \space qt}{1 \space L} \times \frac{8 \space pt}{4 \space qt} = 2.11 \space pt$$ c) $$1 \space gal = 4 \space qt$$ $$1 \ mi = 1.609 \ km$$ $$1 \ \frac{mi}{gal} \times \frac{1.609 \ km}{1 \ mi} \times \frac{1 \ gal}{4 \ qt} \times \frac{1.057 \ qt}{1 \ L} = 0.4252 \frac{km}{L}$$
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