Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Mixed Exercises - Page 39: 69

Answer

$4.1\cdot10^{21}$

Work Step by Step

Convert both measures to meters: $r_H=0.37\ A^{\circ}\cdot \frac{1\ m}{10^{10}\ A^{\circ}}=0.37\cdot10^{-10}\ m$ $r_O=1.5\cdot10^8\ km\cdot\frac{10^3\ m}{1\ km}=1.5\cdot10^{11}\ m$ Find their ratio: $\dfrac{r_O}{r_H}=\dfrac{1.5\cdot10^{11}\ m}{0.37\cdot10^{-10}\ m}$ $\dfrac{r_O}{r_H}=4.1\cdot10^{21}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.