Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Mixed Exercises - Page 39: 71

Answer

$105\ km/h$

Work Step by Step

Use the conversion factor $1\ mi=1.609\ km$: $65\ \frac{mi}h\cdot\frac{1.609\ km}{1\ mi}=105\ km/h$
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