Answer
(a) $CH_{3}$$CH_{2}$OH and (c) $CH_{3}$O$CH_{3}$ will produce the most moles of water while (b) $CH_{3}$OH will generate the least amount of water.
Work Step by Step
1. On combusting organic compounds, the hydrogen present is completely converted to water.
2. Out of the three molecules, $CH_{3}$$CH_{2}$OH and $CH_{3}$O$CH_{3}$ have six H atoms each, while $CH_{3}$OH has only 4 atoms.
3. Therefore, we find that $CH_{3}$$CH_{2}$OH and $CH_{3}$O$CH_{3}$ produce the most moles of water while $CH_{3}$OH generates the least amount of water because of the number of H atoms they have.
