Answer
a) $m(C_{2}H_{3}Cl) = 843.75g$
b) $m(C_{18}H_{27}NO_{3}) =4117.5g$
c) $m(C_{18}H_{36}O_{2}) =3834g$
Work Step by Step
a) $m(C_{2}H_{3}Cl) = M(C_{2}H_{3}Cl) \times n(C_{2}H_{3}Cl)=62.5\frac{g}{mol}\times 13.5mol=843.75g$
b) $m(C_{18}H_{27}NO_{3}) = M(C_{18}H_{27}NO_{3}) \times n(C_{18}H_{27}NO_{3})=305\frac{g}{mol}\times 13.5mol=4117.5g$
c) $m(C_{18}H_{36}O_{2}) = M(C_{18}H_{36}O_{2}) \times n(C_{18}H_{36}O_{2})=284\frac{g}{mol}\times 13.5mol=3834g$
