Answer
a) Ethyl ethanoate
b) Methyl ethanoate
Work Step by Step
a) First, find the functional group present in the molecule. Here, the functional group is $-COO-$. It means the compound is an ester. We divide the molecule into two part while naming ester. First part is alcohol part i.e. on the right side of -COO- group and the second is carboxylic acid part which is on the left side of -COO- group including -COO- group.
Here, alcoholic part has 2 C in it ($CH_{2}CH_{3}$). So, the word root is 'eth' and we add suffix 'yl'. So, the alcoholic part has the name 'ethyl'.
Carboxylic part has 2 C in it including -COO group. i.e. $CH_{3}COO$ part. So, the word root is 'eth' and ending name is 'anoate' for ester group.
So, we write the alcoholic part and after a space write the carboxylic acid part for naming ester. Here, it is 'ethyl ethanoate'.
b) a) First, find the functional group present in the molecule. Here, the functional group is $-COO-$. It means the compound is an ester. We divide the molecule into two part while naming ester. First part is alcohol part i.e. on the right side of -COO- group and the second is carboxylic acid part which is on the left side of -COO- group including -COO- group.
Here, alcoholic part has 1 C in it ($CH_{3}$). So, the word root is 'meth' and we add suffix 'yl'. So, the alcoholic part has the name 'methyl'.
Carboxylic part has 2 C in it including -COO group. i.e. $CH_{3}COO$ part. So, the word root is 'eth' and ending name is 'anoate' for ester group.
So, we write the alcoholic part and after a space write the carboxylic acid part for naming ester. Here, it is 'methyl ethanoate'.
