Answer
a) Phenyl benzoate
b) Ethyl butanoate
Work Step by Step
a) First, find the functional group present in the molecule. Here, the functional group is $-COO-$. It means the compound is an ester. We divide the molecule into two part while naming ester. First part is alcohol part i.e. on the right side of -COO- group and the second is carboxylic acid part which is on the left side of -COO- group including -COO- group.
Here, alcoholic part has a phenyl group in it. So, the alcoholic part has the name 'phenyl'.
Carboxylic acid part has Ph-COO group. So, we add 'benzoate'.
So, we write the alcoholic part and after a space write the carboxylic acid part for naming ester. Here, it is 'phenyl benzoate'.
b) First, find the functional group present in the molecule. Here, the functional group is $-COO-$. It means the compound is an ester. We divide the molecule into two part while naming ester. First part is alcohol part i.e. on the right side of -COO- group and the second is carboxylic acid part which is on the left side of -COO- group including -COO- group.
Here, alcoholic part has 2 C in it ($CH_{2}CH_{3}$). So, the word root is 'eth' and we add suffix 'yl'. So, the alcoholic part has the name 'ethyl'.
Carboxylic acid part has 4 C atoms in it including -COO group. i.e. $CH_{3}CH_{2}CH_{2}COO$ part. So, the word root is 'but' and ending name is 'anoate' for ester group.
So, we write the alcoholic part and after a space write the carboxylic acid part for naming ester. Here, it is 'ethyl butanoate'.
