Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 217: 5.35

Answer

Please see the work below.

Work Step by Step

We know that: $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$ This can be rearranged as: $V_2=\frac{P_1V_1T_2}{T_1P_2}$ We plug in the known values to obtain: $V_2=\frac{1.2\times 2.5\times 25}{248\times 0.003}=840L$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.