Answer
$ 370 L$
Work Step by Step
Given information
Combustion process
$CH_{4} + 2O_{2}-->CO_{2}+2H_{2}O$
15 moles$ CH_{4}$ are reacted
T=23°C=296K
P=0.985 atm
$R=0.0821atmL/molK$
By this reaction, we can say that 15 moles methane gives 15 moles carbon dioxide.
PV=nRT
V(volume of $CO_{2}$)=$\frac{nRT}{P}$
V=$\frac{15*0.0821*296}{0.985}$
V=370L
