Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 217: 5.43

Answer

MM=32

Work Step by Step

PV=nRT (1 atm)(.280L)=$\frac{0.400}{MM}$(0.082)(273.15) MM=$\frac{(0.400)(0.082)(273.15)}{(1)(.0280)}$ MM=31.99757143
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