Chemistry: The Science in Context (4th Edition)

Published by W.W. Norton & Co.
ISBN 10: 0393124177
ISBN 13: 978-0-39312-417-0

Chapter 1 - Matter and Energy: The Origin of the Universe - Problems - Page 38: 72

Answer

$1.39\text{ g/cm}^3$

Work Step by Step

We cakculate the volume: $V=\frac{4\pi}{3}(7\times 10^{10})^3\approx 1.436\times 10^{33}\text{ cm}^3$ Then we determine the density: $\text{Density}=\frac{2\times 10^{33}\text{ g}}{1.436\times 10^{33}\text{ cm}^3}\approx 1.39\text{ g/cm}^3$
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