College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 98: 36

Answer

The force component parallel to the surface = $30N$ The force component perpendicular to the surface =$40N$

Work Step by Step

The force component parallel to the surface = $50cos53^{\circ}=30N$ The force component perpendicular to the surface =$50sin53^{\circ}=40N$
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