Answer
Final displacement vector = $(-8.54x+25.86y)\,m$
And $R=27.3m$, $\theta=72.5^{\circ}$ above negative x-axis.
Work Step by Step
The y-displacement =$20cos60^{\circ}+30-20cos45^{\circ}=25.86m$
The x-displacement= $20cos30^{\circ}-40+20cos45^{\circ}=-8.54m$
So, final displacement vector = $(-8.54x+25.86y)\,m$
And $R=27.3m$, $\theta=72.5^{\circ}$ above negative x-axis.
