Answer
$a). 0.64s, $
$b). 0.64m.$
Work Step by Step
a). Initial vertical component u=0. Thus:
$S=ut+\frac{1}{2}at^{2}$
$2=0+0.5\times9.8t^{2}$
$t=0.64s$
b). Horizontal speed = 1 m/s.
So distance traversed in 0.64s =$ 0.64\times 1=0.64m$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 99: 44
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