Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 99: 51

a). $\theta=46^{\circ}$ b). The plane has traversed 1460m.

a) $S=ut+\frac{1}{2}gt^{2}$ or, $1500=0+0.5\times9.8t^{2}$ $t=17.5s$ Now, $300km/hr=83.3m/s$, Horizontal distance covered=$17.5\times83.3=1460m$ Thus, $\theta=tanx^{-1}\frac{1500}{1460}\approx46^{\circ}$ b) Horizontal distance travelled = 1460m.