Answer
a). When the ball A rolls off the table and hits the floor,(2) ball B will collide with ball A.
b). Horizontal distance covered $=0.11m$
Work Step by Step
a). When the ball A rolls off the table and hits the floor,(2) ball B will collide with ball A. This is because the horizontal velocity is same in magnitude and direction for both balls, also the distance covered will be same.
b). $S=ut+\frac{1}{2}at^{2}$
$0.95=0+0.5\times9.8t^{2}$
$t=0.44s$
Horizontal distance covered in this time$=0.44\times 0.25=0.11m$
