Answer
(a) $B_x = -2.5~m$
$B_y = 4.3~m$
(b) $B_x = 0$
$B_y = 5.0~m$
Work Step by Step
(a) $B_x = -B~sin(\theta)$
$B_x = -(5.0~m)~sin(30^{\circ})$
$B_x = -2.5~m$
$B_y = B~cos(\theta)$
$B_y = (5.0~m)~cos(30^{\circ})$
$B_y = 4.3~m$
(b) From the figure, it is apparent that:
$B_x = 0$
$B_y = 5.0~m$