Answer
$ \vec D = 4.88\hat i + 2.80 \hat j$
Work Step by Step
We have
$ \vec A = 2sin(15^o) \hat i + 2cos(15^o) \hat j $
$\vec A = 0.52 \hat i + 1.92 \hat j$
and $ \vec B = 4cos(15^o) \hat i - 4sin(15^o) \hat j $
$\vec B = 3.84 \hat i - 1.04 \hat j$
Now $ \vec D = 2\vec A + \vec B$
$ \vec D = 2( 0.52 \hat i + 1.92 \hat j) + 3.84 \hat i - 1.04 \hat j$
$ \vec D = 1.04 \hat i + 3.84 \hat j + 3.84 \hat i - 1.04 \hat j$
$ \vec D = 4.88\hat i + 2.80 \hat j$
