Answer
(a) $\theta = 33.6^{\circ}$
(b) $v_y = 1.7~m/s$
Work Step by Step
(a) $v_x = v~cos(\theta)$
$cos(\theta) = \frac{v_x}{v}$
$\theta = arccos(\frac{2.5~m/s}{3.0~m/s})$
$\theta = 33.6^{\circ}$
(b) $v_y = v~sin(\theta)$
$v_y = (3.0~m/s)~sin(33.6^{\circ})$
$v_y = 1.7~m/s$