Answer
a) $2.51\frac{m}{s}$; $61.4^o$
b) $(3.6m, 6.6m)$
Work Step by Step
a) $v=\sqrt{(2.20\frac{m}{s})^2+(1.20\frac{m}{s})^2}=2.51\frac{m}{s}$
$\theta=\arctan\Big(\frac{(2.20\frac{m}{s})^2}{(1.20\frac{m}{s})^2}\Big)=61.4^o$
b) $x=(1.20\frac{m}{s})(3s)=3.6m$
$y=(2.20\frac{m}{s})(3s)=6.6m$
$(3.6m, 6.6m)$
