Answer
The maximum force that the motor should exert on the cable is 50,700 N.
The minimum force that the motor should exert on the cable is 44,300 N.
Work Step by Step
Maximum force:
$F_T - mg = ma$
$F_T = ma + mg$
$F_T = m(a+g)$
$F_T = (4850 ~kg)(1.0680\times 9.80 m/s^2)$
$F_T = 50,762 ~N$
$F_T \approx 50,762 ~N$
The maximum force that the motor should exert on the cable is 50,700 N.
Minimum force:
$mg - F_T = ma$
$F_T = mg - ma$
$F_T = m(g-a)$
$F_T = (4850 ~kg)(0.932\times 9.80 m/s^2)$
$F_T = 44,298 ~N$
$F_T \approx 44,300 ~N$
The minimum force that the motor should exert on the cable is 44,300 N.
