Answer
The average force required to stop the car is -3100 N.
Work Step by Step
$v = (95 ~\frac{km}{h})(\frac{1000 ~m}{1 ~km})(\frac{1 ~h}{3600 ~s})$
$v = 26.39m/s$
$a = \frac{v-v_0}{t}$
$a = \frac{-26.39 m/s}{8.0 ~s}$
$a = -3.299 m/s^2$
The magnitude of the acceleration is $3.299m/s^2$.
$F = ma$
$F = (950 ~kg)(-3.299~m/s^2)$
$F = -3133.7~N$
$F \approx -3100~N$
The average force required to stop the car is -3100 N.
