Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 101: 4

Answer

0.02 N.

Work Step by Step

Find the average acceleration of the blood. $$\frac{0.35 m/s – 0.25 m/s}{0.10 s}=1.0 \frac{m}{s^{2}}$$ Use Newton’s second law to find the required net force on the blood, exerted by the heart muscle. The answer is rounded to 2 significant figures. $$\Sigma F=ma=(0.020 kg)(1.0 \frac{m}{s^{2}})= 0.02 N $$
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