Answer
They will not get fogged.
Work Step by Step
The vapor pressure $P_v$ of the air in the house is uniform throughout, and its value can be determined from $$
P_v=\phi P_{g @ 25^{\circ \mathrm{C}}}=(0.30)(3.1698 \mathrm{kPa})=0.9509\ \mathrm{kPa}
$$ The dew-point temperature of the air in the house is $$
T_{\mathrm{dp}}=T_{\mathrm{sat} @ P_{\mathrm{s}}}=T_{\text {sat } \alpha 0.950 \% \mathrm{pu}}=6.2^{\circ} \mathrm{C} \text { (Table A-5 or EES) }
$$ That is, the moisture in the house air will start condensing when the air temperature drops below $6.2^{\circ} \mathrm{C}$. Since the glasses are at a higher temperature than the dew-point temperature, moisture will not condense on the glasses, and thus they will not get fogged.
