Answer
See explanation
Work Step by Step
From the psychrometric chart (Fig. A-31) we read
(a) $\omega=0.0092 \mathrm{~kg~} \mathrm{H}_2 \mathrm{O} / \mathrm{kg}$ dry air
(b) $h=47.6 \mathrm{~kJ} / \mathrm{kg}$ dry air
(c) $\phi=49.6 \%$
(d) $T_{\mathrm{dp}}=12.8^{\circ} \mathrm{C}$
(e) $\boldsymbol{v}=0.855 \mathrm{~m}^3 / \mathrm{kg}$ dry air
