Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 14 - Gas-Vapor Mixtures and Air-Conditioning - Problems - Page 750: 14-27

Answer

It will sweat.

Work Step by Step

The vapor pressure $P_v$ of the air in the house is uniform throughout, and its value can be determined from $$ P_v=\phi P_{g @ 70^{\circ} \mathrm{F}}=(0.38)(0.3633 \mathrm{psia})=0.1381\ \mathrm{psia} $$ The dew-point temperature of the air in the house is $$ T_{\mathrm{dp}}=T_{\text {sat } @ P_\gamma}=T_{\text {sat } @ 0.138 \text { lpsia }}=43.3^{\circ} \mathbf{F} \text { (from EES) } $$ That is, the moisture in the house air will start condensing when the air temperature drops below $43.3^{\circ} \mathrm{C}$. Since the canned drink is at a lower temperature than the dew-point temperature, some moisture will condense on the can, and thus it will sweat.
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