Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 8 - Exergy - Problems - Page 483: 8-140

Answer

B

Work Step by Step

From the definitions: $COP_{HP,rev}=\dfrac{T_H}{T_H-T_L}$ With $T_H=294\ K,\ T_L=T_0=282\ K$ $COP_{HP,rev}=24.5$ $COP_{actual}=COP_{res.\ heater}=1$ $\eta_{_{II}}=\dfrac{COP_{actual}}{COP_{rev}}=4.08\%$
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