Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 8 - Exergy - Problems - Page 483: 8-141

Answer

D

Work Step by Step

From the definition: $X=m\left[c_p(T_1-T_0)-T_0c_p\ln{\dfrac{T_1}{T_0}}\right]$ Given $m=12\ kg,\ c_p=2.8\ kJ/kg.K,\ T_1=263\ K,\ T_0=293\ K$ $X=55.4\ kJ$
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