Answer
C
Work Step by Step
From the definitions:
$\eta_{rev}=1-\dfrac{T_L}{T_H}=\dfrac{\dot{W}_{max}}{\dot{Q}_{in}}$
Given $T_L=300\ K,\ T_H=1300\ K,\ \dot{Q}_{in}=500\ kJ/s$
$\dot{W}_{max}=384.6\ kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 8 - Exergy - Problems - Page 483: 8-143
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